## Rotate

This post is inspired by one of those classic "99 problems in Prolog".What we are looking for here are two functions that satisfy these signatures.

val rotate_left : int -> α list -> α list val rotate_right : int -> α list -> α list

`rotate_left n`

rotates a list $n$ places to the left, `rotate_right n`

rotates a list $n$ places to the right. Examples:
# rotate_left 3 ['a';'b';'c';'d';'e';'f';'g';'h'] ;; - : char list = ['d'; 'e'; 'f'; 'g'; 'h'; 'a'; 'b'; 'c'] # rotate_left (-2) ['a';'b';'c';'d';'e';'f';'g';'h'] ;; - : char list = ['g'; 'h'; 'a'; 'b'; 'c'; 'd'; 'e'; 'f']Of course,

`rotate_left`

and `rotate_right`

are inverse functions of each other so we expect, for any int $x$ and list $l$, `rotate_right x @@ rotate_left x l`

$=$ `rotate_left x @@ rotate_right x l`

$=$ `l`

.
Well, there are a variety of solutions to this problem with differing degrees of verbosity, complexity and efficiency. My own attempt at a solution resulted in this.

let rec drop (k : int) (l : α list) : α list = match k, l with | i, _ when i <= 0 -> l | _, [] -> [] | _, (_ :: xs) -> drop (k - 1) xs let rec take (k : int) (l : α list) : α list = match k, l with | i, _ when i <= 0 -> [] | _, [] -> [] | _, (x :: xs) -> x :: take (k - 1) xs let split_at (n : int) (l : α list) : α list * α list = (take n l), (drop n l) let rec rotate_left (n : int) (l : α list) : α list = match n with | _ when n = 0 -> l | _ when n < 0 -> rotate_right (-n) l | _ -> let m : int = List.length l in let k : int = n mod m in let (l : α list), (r : α list) = split_at k l in r @ l and rotate_right (n : int) (l : α list) : α list = match n with | _ when n = 0 -> l | _ when n < 0 -> rotate_left (-n) l | _ -> let m : int = List.length l in let k : int = m - n mod m in let (l : α list), (r : α list) = split_at k l in r @ l

So far so good, but then I was shown the following solution in Haskell.

rotateLeft n xs | n >= 0 = take (length xs) $ drop n $ concat $ repeat xs | otherwise = rotateLeft (length xs + n) xs rotateRight n = rotateLeft (-n)I found that pretty nifty! See, in the function

`rotateLeft`

, `repeat xs`

creates an infinite list of lists, (each a copy of `xs`

), `length xs`

which gets us the original list rotated left $n$ places.
I felt compelled to attempt to emulate the program above in OCaml.

The phrasing "works" in Haskell due to the feature of lazy evaluation. OCaml on the other hand is eagerly evaluated. Lazy evaluation is possible in OCaml however, you just need to be explicit about it. Here's a type for "lazy lists" aka "streams".

type α stream = Nil | Cons of α * α stream Lazy.t

*A value of type*`α Lazy.t`

is a deferred computation, called a suspension that has the result type `α`

. The syntax `lazy`

$(expr)$ makes a suspension of $expr$, without yet evaluating $expr$. "Forcing" the suspension (using `Lazy.force`

) evaluates $expr$ and returns its result.Next up, functions to get the head and tail of a stream.

let hd = function | Nil -> failwith "hd" | Cons (h, _) -> h let tl = function | Nil -> failwith "tl" | Cons (_, t) -> Lazy.force tAlso useful, a function to lift an

`α list`

to an `α stream`

.
let from_list (l : α list) : α stream = List.fold_right (fun x s -> Cons (x, lazy s)) l Nil

Those are the basic building blocks. Now we turn attention to implementing `repeat x`

to create infinite lists of the repeated value $x$.

let rec repeat (x : α) : α stream = Cons (x, lazy (repeat x))

Now to implement `concat`

(I prefer to call this function by its alternative name `flatten`

).

The characteristic operation of `flatten`

is the joining together of two lists. For eager lists, we can write a function `join`

that appends two lists like this.

let rec join l m = match l with | [] -> m | h :: t -> h :: (join t m)This generalizes naturally to streams.

let rec join (l : α stream) (m : α stream) = match l with | Nil -> m | Cons (h, t) -> Cons (h, lazy (join (Lazy.force t) m))For eager lists, we can write

`flatten`

in terms of `join`

.
let rec flatten : α list list -> α list = function | [] -> [] | (h :: tl) -> join h (flatten tl)Emboldened by our earlier success we might try to generalize it to streams like this.

let rec flatten (l : α stream stream) : α stream = match l with | Nil -> lazy Nil | Cons (l, r) -> join l (flatten (Lazy.force r))Sadly, no. This definition is going to result in stack overflow. There is an alternative phrasing of

`flatten`

we might try.
let rec flatten = function | [] -> [] | [] :: t -> flatten t | (x :: xs) :: t -> x :: (flatten (xs :: t))Happy to say, this one generalizes and gets around the eager evaluation problem that causes the unbounded recursion.

let rec flatten : α stream stream -> α stream = function | Nil -> Nil | Cons (Nil, t) -> flatten (Lazy.force t) | Cons (Cons (x, xs), t) -> Cons (x, lazy (flatten (Cons (Lazy.force xs, t))))

`take`

and `drop`

are straight forward generalizations of their eager counterparts.

let rec drop (n : int) (lst : α stream ) : α stream = match (n, lst) with | (n, _) when n < 0 -> invalid_arg "negative index in drop" | (n, xs) when n = 0 -> xs | (_, Nil) -> Nil | (n, Cons (_, t)) -> drop (n - 1) (Lazy.force t) let rec take (n : int) (lst : α stream) : α list = match (n, lst) with | (n, _) when n < 0 -> invalid_arg "negative index in take" | (n, _) when n = 0 -> [] | (_, Nil) -> [] | (n, Cons (h, t)) -> h :: (take (n - 1) (Lazy.force t))

Which brings us to the lazy version of `rotate`

expressed in about the same number of lines of code!

let rec rotate_left (k : int) (l : α list) : α list = let n = List.length l in if k >= 0 then l |> from_list |> repeat |> flatten |> drop k |> take n else rotate_left (n + k) l let rotate_right (n : int) : α list -> α list = rotate_left (-n)